Dusan7
Answered

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Answer the questions below​

Answer The Questions Below class=

Sagot :

mhanifa

Answer:

#1

At the start the total number is 10, male fish = 6

  • P(m) = 6/10 = 3/5

At the second time the total number is 9, male fish = 5

  • P(m) = 5/9

Probability of two male fish is:

  • P(m and m) = 3/5*5/9 = 1/3

#2

  • a) The events are independent
  • b) P(4 and A) = 1/6*1/4 = 1/24
  • c) P(an even number and C) = 1/3*1/4 = 1/12
  • d) P(2 or 5 and B or D) = (1/6 + 1/6)*(1/4 + 1/4) = 1/3*1/2 = 1/6

#3

  • P(both goals) = 0.8*0.8 = 0.64
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