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Mg (s) + 2 HCl (aq) --> MgCl2 (aq) + H2 (g)

Use the equation above to determine the number of grams of magnesium chloride, MgCl2 , that can be produced if 4.00 moles of HCl (hydrochloric acid) react. please show all work and record your answer with proper units and significant figures.
Pls help

Sagot :

Trancescient

Answer:

m = 190. g MgCl2

Explanation:

Use a molar ratio to get the # of moles MgCl2 produced from 4.00 mol of HCl:

4.00 mol HCl × (1 mol MgCl2/2 mol HCl) = 2.00 mil MgCl2

So 2.00 moles of MgCl2 will be produced. To find the mass in grams, use the molar mass of MgCl2:

2.00 mol MgCl2 × (95.211 g MgCl2/1 mol MgCl2)

= 190. g MgCl2

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