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Sagot :

Answer:

a^2 +b^2=c^2

Given vertices of the triangle are A(4,4),B(3,5) and C(−1,−1)

We know that slope of line passing through the points (x 1,y 1) and (x 2,y 2

) is given by m= x 2−x 1

y

2

−y

1

,x

2

=x

1

Slope of AB i.e.m

1

=

3−4

5−4

=−1

Slope of BC i.e.m

2

=

−1−3

−1−5

=

−4

−6

=

2

3

Slope of CA i.e. m

3

=

4+1

4+1

=

5

5

=1

Clearly, m

1

m

3

=−1

⇒ line segments AB and CA are perpendicular to each other i.e; the given triangle is right angled at A(4,4).

Thus the points (4,4),(3,5) and (1,1) are the vertices of a right angled triangle.

Step-by-step explanation: