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A circus juggler on the highwire gives a bowling pin a final toss into the air with an initial velocity of 9 meters per second from a height of 11 meters. The equation h(t)=

4.9t2+9t+11 models the height of the bowling pin in meters after t seconds.
About how many seconds does it take for the bowling pin to hit the ground?
Round your answer to the nearest tenth of a second.


Sagot :

Answer:

2.7

Step-by-step explanation:

yes i'm correct

A circus juggler on the highwire gives a bowling pin a final toss into the air with an initial velocity of 9 meters per second from a height of 11 meters. The time taken by the object to hit the ground is 2.7 seconds.

What is a quadratic equation?

A quadratic equation is the second-order degree algebraic expression in a variable.

The standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

It is given that,

Initial velocity of an object, u = 9 m/s

Height, h = 11 m

The equation that models the height of the object in meters after t seconds is :

[tex]h(t)= -4.9t^2+9t+11[/tex]

We have to find the time it take for the bowling pin to hit the ground

i.e.   [tex]-4.9t^2+9t+11=0[/tex]

On solving the above quadratic equation, we get the value of time t is :

t = 2.7 seconds

Hence, The time it takes to hit the ground would be 2.7 seconds.

Learn more about quadratic equations here:

https://brainly.com/question/3358603

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