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A truck rental company rents a moving truck One Day by charging $39 + 0.09 per mile write a linear equation that relates the cost c in dollars of renting the truck to the number x of miles driven and what is the cost of renting the truck if the truck is driven 160 MI

Sagot :

Answer:

[tex](a)\ c(x) = 39 + 0.09 x[/tex]

[tex](b)\ \$53.4[/tex]

Step-by-step explanation:

Given

[tex]Base\ Charge = \$39[/tex]

[tex]Rate = 0.09[/tex] per mile

Solving (a): Linear Equation

The total charges (c(x)) is: the base charge + the rate * number of miles (x).

So, we have:

[tex]c(x)= 39 + 0.09 * x[/tex]

[tex]c(x) = 39 + 0.09 x[/tex]

Solving (b): Cost of rent, if miles = 160

This implies that x = 160

So, we have:

[tex]c(x) = 39 + 0.09 x[/tex]

[tex]c(160) = 39 + 0.09 *160[/tex]

[tex]c(160) = 39 + 14.4[/tex]

[tex]c(160) = 53.4[/tex]