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Sagot :
Given:
A circle with diameter 9 cm.
To find:
The area of the circle.
Solution:
The area of a circle is:
[tex]A=\pi r^2[/tex] ...(i)
Where r is the radius.
We know that, the diameter of a circle is twice than its radius.
The diameter of the given circle is 9 cm.
[tex]r=\dfrac{9}{2}[/tex]
[tex]r=4.5[/tex]
Substituting [tex]r=4.5, \pi =3.14[/tex] in (i), we get
[tex]A=(3.14)(4.5)^2[/tex]
[tex]A=(3.14)(20.25)[/tex]
[tex]A=63.585[/tex]
[tex]A\approx 63.6[/tex]
Therefore, the area of the given circle is 63.6.
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