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Sagot :
The width of the border will be about 2.5 feet.
The area of the rug is 9 by 7. Let's call the width of the border x. Therefore, the length of the rug will switch to 9 + 2x. The border is on both sides of it, so we add on 2x. Then, the width is 7 + 2x.
The area of the room is therefore: (9 + 2x)(7+ 2x).
We know the area of the room, so we can write and solve the following equation.
(9 + 2x)(7 + 2x) = 167
4x^2 + 32x + 63 = 167
4x^2 + 32x - 107 = 0
At this point, use the quadratic formula and x will equal about 2.5.
The area of the rug is 9 by 7. Let's call the width of the border x. Therefore, the length of the rug will switch to 9 + 2x. The border is on both sides of it, so we add on 2x. Then, the width is 7 + 2x.
The area of the room is therefore: (9 + 2x)(7+ 2x).
We know the area of the room, so we can write and solve the following equation.
(9 + 2x)(7 + 2x) = 167
4x^2 + 32x + 63 = 167
4x^2 + 32x - 107 = 0
At this point, use the quadratic formula and x will equal about 2.5.
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