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2. A loop of wire of area 0.7 m is moving into a 0.9 T magnetic field. If it takes 5
seconds for the loop to move from completely outside the field to completely inside the
field, what emf is produced?


Sagot :

Answer:

fem = -0.126 V

Explanation:

Faraday's law is

          fem =  [tex]- \frac{d \phi}{dt}[/tex]

where the flow is

          Ф = B . A = B A cos θ

bold letters indicate vectors.

In this case, the normal to the area is parallel to the magnetic field, so the angle is zero and the cos0 = 1

           fem = [tex]- A \ \frac{dB}{dt}[/tex]

in this case they indicate that to carry the loop from outside to inside the field in Δt = 5 s, so we can change them by variations

           fem = [tex]- A \frac{\Delta B}{\Delta t}[/tex]

let's calculate

           fem = - 0.7 (0.9 -0) / 5

           fem = -0.126 V