flackogutierrez
Answered

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1) A negative charge of 6C exerts an attractive force of 65N on a second
charge that is 0.005 m away. What is the strength of the second charge?

Sagot :

Answer: [tex]30.09\times 10^{-15}\ C[/tex]

Explanation:

Given

The first charge is [tex]q_1=-6\ C[/tex]

Attraction force [tex]F=65\ N[/tex]

the second charge is at [tex]0.005\ m[/tex] away

Suppose the second charge is [tex]q_2[/tex]

The electrostatic force is given by

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Insert the values

[tex]65=\dfrac{9\times 10^9\times 6\times q_2}{[5\times 10^{-3}]^2}\\\\\Rightarrow q_2=\dfrac{65\times 25\times 10^{-6}}{54\times 10^9}\\\\\Rightarrow q_2=\dfrac{1625\times 10^{-6-9}}{54}\\\\\Rightarrow q_2=30.09\times 10^{-15}\ C[/tex]

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