Answered

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determine the number of grams of sodium carbonate needed to prepare 100.0 ml of a 2.5 m solution

Sagot :

maacastrobr

Answer:

26.5 g

Explanation:

First we convert 100.0 mL to L:

  • 100.0 mL / 1000 = 0.100 L

Now we calculate how many moles of sodium carbonate are needed, using the definition of molarity:

  • Molarity = moles / liters
  • moles = molarity * liters
  • 2.5 M * 0.100 L = 0.25 mol

Finally we convert 0.25 moles of sodium carbonate into grams, using its molar mass:

  • 0.25 mol * 106 g/mol = 26.5 g
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