Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Find the number of grams of calcium chloride needed to prepare 500.0ml of a 4.0m solution

Sagot :

maacastrobr

Answer:

222 g

Explanation:

First we convert 500.0 mL to L:

  • 500.0 mL / 1000 = 0.500 L

Then we use the definition of molarity to calculate how many calcium chloride moles are required:

  • Molarity = moles / liters
  • Molarity * liters = moles
  • 4.0 M * 0.500 L = 2.00 mol

Now we convert 2.00 moles of calcium chloride into grams, using its molar mass:

  • 2.00 mol * 111 g/mol = 222 g
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.