Answered

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Find the number of grams of calcium chloride needed to prepare 500.0ml of a 4.0m solution

Sagot :

maacastrobr

Answer:

222 g

Explanation:

First we convert 500.0 mL to L:

  • 500.0 mL / 1000 = 0.500 L

Then we use the definition of molarity to calculate how many calcium chloride moles are required:

  • Molarity = moles / liters
  • Molarity * liters = moles
  • 4.0 M * 0.500 L = 2.00 mol

Now we convert 2.00 moles of calcium chloride into grams, using its molar mass:

  • 2.00 mol * 111 g/mol = 222 g
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