Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

How much thermal energy must be removed from a 0.25 kg chunk of ice to lower its temperature by 7°C? Specific heat capacity of ice is 2020 J/kg^ C .

Sagot :

The Formula we use to work out this question is:

Q=m*c*ΔT

Where,

  • Q= Thermal Energy (J)
  • m= Mass of object (kg)
  • c= Specific heat capacity (J/kg^C)
  • ΔT = Change in Temperature. (°C)

Firstly we want to substitute the values in: (Note, ΔT is Negative as we are lowering the temperature)

Q=0.25kg * 2020J/kg^ C * (-7°C)

This gives us:

Q= -3535 J.

This means that 3535J of thermal energy must be removed from the block of ice in order to lower its temperature by 7°C.

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.