This problem is providing information about the titration of sulfuric acid with sodium hydroxide in order to neutralize the acid. It is required to describe how to find out the difference concentration on P and Q via titration.
In such a case, we should firstly write out the chemical reaction that takes place when sulfuric acid is neutralized by sodium hydroxide to form sodium sulfate and water:
[tex]2NaOH(aq)+ H_2SO_4\rightarrow Na_2SO_4 (aq)+2H_2O(l)[/tex]
The aforesaid means that at the equivalence point, the following equation will be valid for the moles of the acid and the base:
[tex]2n_{acid}=n_{base}[/tex]
Which can be written in terms of volume and concentration for the both of them:
[tex]2M_{acid}V_{acid}= M _{base} V_{base}[/tex]
Thus, we can solve for the molarity of the acid to obtain:
[tex]M_{acid}= \frac{M _{base} V_{base}}{2V_{acid}}[/tex]
This equation can be used to calculate the molarity of both samples of acid, if you know their volume, the concentration of the base and its volume, which are measurements and values you can obtain from your experiments.
Learn more:
- https://brainly.com/question/25485091
- https://brainly.com/question/12758584
