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Sagot :
Answer:
1. We would hear better at Dunkin's since its distance from the radio station is the shortest.
2. McDonald's is out of range of the radio station since its distance is greater than the range of the radio station.
Step-by-step explanation:
1) Will we hear it better at Zaxby's (2,-4), McDonalds (4, -4), or Dunkin' (-3,3). Show work to support your decision and explain your reasoning.
We need to find the distance of each point from the tower.
The shorter the distance from the radio station the better the signal.
The distance between two points (x₁, y₁) and (x₂, y₂) is given by d = √[(x₂ - x₁)² + (y₂ - y₁)²].
With (x₁, y₁) = (0, 0) the location of local station WDHS
For Zaxby's distance located at (2, -4) = (x₂, y₂)
So, d₁ = √[(x₂ - x₁)² + (y₂ - y₁)²]
= √[(2 - 0)² + (-4 - 0)²]
= √[(2)² + (-4)²]
= √[4 + 16]
= √20
= √(5 × 4)
= √5 × √4
= 2√5
= 4.47 miles
For McDonald's distance located at (4, -4) = (x₂, y₂)
So, d₂ = √[(x₂ - x₁)² + (y₂ - y₁)²]
= √[(4 - 0)² + (-4 - 0)²]
= √[(4)² + (-4)²]
= √[16 + 16]
= √32
= √(16 × 2)
= √16 × √2
= 4√2
= 5.66 miles
For Dunkin's distance located at (-3, 3) = (x₂, y₂)
So, d₃ = √[(x₂ - x₁)² + (y₂ - y₁)²]
= √[(-3 - 0)² + (-3 - 0)²]
= √[(-3)² + (-3)²]
= √[9 + 9]
= √18
= √(9 × 2)
= √9 × √2
= 3√2
= 4.24 miles
Since Dunkin's distance, d₃ = 4.24 is the least distance from the radio station and is within range of 5 miles, we would hear better at Dunkin's.
2) Are any of these location outside the range of the radio station? If so, which one(s). Defend your decision mathematically.
The radio station is outside of range if its distance is greater than 5 miles. That is, d > 5 miles.
So, we calculate the distance of each point from the radio station.
With (x₁, y₁) = (0, 0) the location of local station WDHS
For Zaxby's distance located at (2, -4) = (x₂, y₂)
So, d₁ = √[(x₂ - x₁)² + (y₂ - y₁)²]
= √[(2 - 0)² + (-4 - 0)²]
= √[(2)² + (-4)²]
= √[4 + 16]
= √20
= √(5 × 4)
= √5 × √4
= 2√5
= 4.47 miles
For McDonald's distance located at (4, -4) = (x₂, y₂)
So, d₂ = √[(x₂ - x₁)² + (y₂ - y₁)²]
= √[(4 - 0)² + (-4 - 0)²]
= √[(4)² + (-4)²]
= √[16 + 16]
= √32
= √(16 × 2)
= √16 × √2
= 4√2
= 5.66 miles
For Dunkin's distance located at (-3, 3) = (x₂, y₂)
So, d₃ = √[(x₂ - x₁)² + (y₂ - y₁)²]
= √[(-3 - 0)² + (-3 - 0)²]
= √[(-3)² + (-3)²]
= √[9 + 9]
= √18
= √(9 × 2)
= √9 × √2
= 3√2
= 4.24 miles
So, for each of the distances calculated above, only McDonald's distance, d₂ = 5.66 miles > 5 miles.
So, McDonald's is out of range of the radio station.
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