Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

B) A company president would like to offer a 4.00 L cylinder containing 500 g of chlorine in the new catalog. The cylinders you have on hand have a rupture pressure of 40 atm. Use both the ideal gas law and the van der Waals equation to calculate the pressure in a cylinder at 25°C. Given a = 6.58 L2 atm mol-2 and b = 0.056 L mol-2, Cl =35.5. (5 marks)

Sagot :

jufsanabriasa

Answer:

43.1atm is the pressure using gas law and 27.2atm using Van der Waals Law.

Explanation:

Ideal gas law is:

PV = nRT

Where P is pressure in atm

V is volume = 4.00L

n are moles of the gas (For chlorine Molar Mass: 70.90g/mol):

500g * (1mol / 70.90g) = 7.052 moles

R is gas constant = 0.082atmL/molK

T is absolute temperature = 25°C + 273 = 298K

To solve the pressure, P:

P = nRT/V

P = 7.052mol*0.082atmL/molK*298K / 4.00L

P = 43.1atm is the pressure using gas law.

Van der Waals equation is:

[tex]P + a(\frac{n}{V})^2 * (V-nb) = nRT[/tex]

Where a is 6.58L²atm*mol⁻²

b = 0.056Lmol⁻²

Solving for pressure:

[tex]P + a(\frac{n}{V})^2 = \frac{nRT}{(V-nb)}[/tex]

[tex]P = \frac{nRT}{(V-nb)}-a(\frac{n}{V})^2[/tex]

[tex]P = \frac{7.052mol*0.082atmL/molK*298K}{(4.00L-7.052mol*0.056L*mol)}-6.58L^2mol^{-2}(\frac{7.052mol}{4.00L})^2[/tex]

P = 172.323 / 3.6051 - 20.4866

P = 27.2atm using Van der Waals Law

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.