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Sagot :
Answer:
307.07N
Explanation:
Given
Weight of object = 250N
angle of elevation = 18.0°
coefficient of kinetic friction n = 0.26
acceleration = 9.81m/s^2
Required
Force parallel to the ramp
Using Newton second law
F = ma
Fm - Ff = ma
Fm - nR = ma
Fm = ma +nR
Fm = 25(9.81) + 0.26(Wcostheta)
Fm = 25(9.81) + 0.26(250cos18)
Fm = 245.25+61.81
Fm = 307.07N
Hence he magnitude of the force that the rope exerts on the crate parallel to the ramp is 307.07N
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