Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer:
x2 + 8x – 65 = 0
Step-by-step explanation:
Complete question
A square picture with a side length of 4 inches needs to be enlarged. The final area needs to be 81 square inches. Which equation can be used to solve for x, the increase in side length of the square in inches? x2 + 4x – 81 = 0 x2 + 4x – 65 = 0 x2 + 8x – 65 = 0 x2 + 8x – 81 = 0
Given the initial side length = 4in
Initial area = L²
L is side length of the square
Initial area = 4²
Initial area = 16 square inches
Area of the enlarged square = 81 square inches
To get the constant term of the expression, we will find the difference in the areas
Difference = 85 - 16
Difference = 65 square units
The coefficient of x will be the 2 *initial area of the square
Given the standard form of an expression as
ax^2 + bx + c
a = 1, b = 2*4 = 8, c = -65
Substitute
x^2 + 8x - 65
This gives the required expression
Answer:
C) x2 + 8x – 65 = 0
Step-by-step explanation:
edge
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.