Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A 12-volt battery causes 0.60 ampere to flow through a circuit that contains a lamp and a resistor connected in parallel. The lamp is operating at 6.0 watts.
Calculate the resistance of the resistor.

A: 7.2
B: 60
C: 72
D: 120


Sagot :

The answer to this question is A

The resistance of the resistor is 120 Ω

What is resistance?

"Resistance is a measure of the opposition to current flow in an electrical circuit."

Data given

Power of lamp (P)= 6 W,

Emf of cell (V)= 12 Volt

Current drawn from cell (i) = 0.6 A

Combination is parallel, it means the potential on resistor and lamp is same, so current taken by lamp, by formula,

P= V .i

Substitute the values,

6 = 12× i

i = [tex]\frac{6}{12}[/tex]

i = 0.5 A ( current taken by lamp) so current taken by resistor,

[tex]i_{r} = 0.6-0.5 =0.1 A[/tex]

Now the resistance of resistor, by formula,

[tex]R = \frac{V}{i_{r} }[/tex]

[tex]R = \frac{12}{0.1} \\R = 120[/tex] Ω

Hence the resistance of the resistor is 120 Ω.

To learn more about resistance here

https://brainly.com/question/17562635

#SPJ2