Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
The particle moves to the right when 0 ≤ t < a
Explanation:
Since at any time t≥0 its position is given by x(t) = 12(a−t)², the particle moves to the right if x(t) > 0
So, x(t) > 0 ⇒ 12(a−t)² > 0 ⇒ (a−t)² > 0
So, (a−t)² > 0
taking square-root of both sides, we have
√(a−t)² > √0
⇒ (a−t) > 0
⇒ a > t
Since t ≥ 0 ⇒ a > t ≥ 0 ⇒ 0 ≤ t < a
So, the particle moves to the right when 0 ≤ t < a
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.