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Sagot :
Answer: [tex]232.8\ K[/tex]
Explanation:
Given
The volume of Nitrogen gas is [tex]V_1=3.5\times 10^{-2}\ m^3[/tex]
Pressure is [tex]P_1=10^5\ Pa[/tex]
Temperature [tex]T_1=291\ K[/tex]
When the pressure and temperature changes i.e.
[tex]P_2=10^5\ Pa[/tex]
[tex]V_2=2.8\times 10^{-2}\ m^3[/tex]
Temperature is given by
[tex]\Rightarrow \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\\\Rightarrow T_2=\dfrac{P_2V_2}{P_1V_1}\times T_1[/tex]
Insert values
[tex]\Rightarrow T_2=\dfrac{2.8\times 10^{-2}\times 10^5}{3.5\times 10^{-2}\times 10^5}\times 291\\\\\Rightarrow T_2=291\times 0.8\\\Rightarrow T_2=232.8\ K[/tex]
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