inderpreet
Answered

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Given the equations 2x + 2y = 16 and 4x - 3y = -3, what are the values of x and y?

Sagot :

Porshia
Steps:
1. Put 2x + 2y=16 into slope-intercept form
2. Subtract 2x on both sides
2y= -2x + 16
3. Divide by 2 on both sides
Y= -x + 8
4. Substitute the y in 4x -3y=-3 for -x + 8
4x -3(-x + 8)= -3
5. Multiply everything in parentheses
4x + 3x + (-24)= -3
7x + (-24)=-3
6. Add 24 on both sides
7x=21
7. Divide by 7
8. X= 3
9. Substitute the x for a 3 in one of the equations
Y=-x + 8
Y= -3 + 8
Y=5
10. Your answers are
X= 3 Y= 5

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