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Sagot :
[tex]\huge\longmapsto\mathfrak{Answer}[/tex]
=》
[tex] \sec {}^{2} (x) - tan(x) - 3[/tex]
=》
[tex] \tan {}^{2} (x) + 1 - \tan(x) - 3[/tex]
=》
[tex] \tan {}^{2} (x) - \tan(x) - 2[/tex]
=》
[tex] \tan {}^{2} (x) - 2\tan(x) + \tan(x) - 2[/tex]
=》
[tex] \tan(x) ( \tan(x) - 2) + 1( \tan(x) - 2) [/tex]
=》
[tex]( \tan(x) + 1)( \tan(x) - 2)[/tex]
so,
case - 1
=》
[tex] \tan(x) = - 1[/tex]
case - 2
[tex] \tan(x) = 2[/tex]
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