Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

The function f(n)=100(0.25)^n represents the amount of radioactive substance left after n hours. At what rate in percent is the amount of radioactive substance changing

Sagot :

fichoh

Answer:

75%

Step-by-step explanation:

Given the function :

f(n)=100(0.25)^n

Comparing the function with

y = a(1 - r)^t

From. The equation, r = rate

Comparing with the value in bracket in the question given :

1 - r = 0.25

1 - 0.25 = r

0.75 = r

Hence, r = 0.75

As a percentage, rate = 0.75 * 100% = 75%

Hence, the rate of change is 75%

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.