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Una pelota sale disparada desde el nivel del suelo, con una velocidad de 40 m/s y un ángulo de elevación de 50°. a) Calcule la altura máxima que alcanza la pelota

Sagot :

abidemiokin

Respuesta:

Los 47.85m

Explicación paso a paso:

Altura máxima = u²sin²Ф / 2g

Dado

velocidad u = 40 m / s

Ф = 50 °

g = 9,81 m / s²

Sustituir'

H = 40²sin²50 / 2 (9,81)

H = 1600 (0,7660) ² / 19,62

H = 1600 (0,5868) /19,62

H = 938,8096 / 19,62

H = 47,85 m

Por lo tanto, la altura máxima es de 47,85 m.

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