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Sagot :
9514 1404 393
Answer:
4 acres each of wheat and rye
Step-by-step explanation:
Let x and y represent acres of wheat and rye, respectively. Then the constraints of the problem are ...
200x +100y ≤ 1200 . . . . . . cost constraint
x + 2y ≤ 12 . . . . . . . . . . . time constraint
The objective is to maximize profit (p):
p = 500x +300y
The constraints can be graphed (see attached). The profit function will be maximized at one of the vertices of the "feasible region," the portion of the graph that satisfies the constraints. The vertices are (x, y) = (0, 6), (4, 4), and (6, 0). The associated profit values are $1800, $3200, and $3000.
Maximum profit is obtained when 4 acres of wheat and 4 acres of rye are planted.
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