Answered

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Imagine a proton at rest a certain distance from a negatively charged plate. It is released and collides with the plate. Then imagine the similar case of an electron at rest, the same distance away, from a plate of equal and opposite charge. In which case would the moving particle have the greater speed when the collision occurs

Sagot :

Answer:

v_e »v_proton

Explanation:

To analyze which body has more energy, let's use the concepts of energy

starting point. Before releasing the particle

           Emo = U = e V

final point.

           Em_f = K = ½ m v²

energy is conservative

          Em₀ = em_f

          eV = ½ m v²

          v² = 2eV / m

we see that the velocity of the body is inversely proportional to the mass of the atom.

For the present cao the mass of the proton is much greater than the mass of the electron

which

           v_e »v_proton

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