jaminluke04
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How many kilojoules of heat are required to heat 2550 grams of water from 17.5°C to 100.0°C?

Sagot :

samueladesida43

880.209 kilojoules of heat are required to heat 2550 grams of water from 17.5°C to 100.0°C.

HOW TO CALCULATE SPECIFIC HEAT:

The amount of energy released or absorbed by a substance can be calculated using the following expression:

Q = m × c × ∆T

where;

  • Q = quantity of heat in Joules
  • m = mass of substance
  • ∆T = change in temperature

According to this question;

  • m = 2550g
  • ∆T = 100 - 17.5 = 82.5°C

Q = 2550 × 4.184 × 82.5

Q = 880,209J

Q = 880.209kJ.

Therefore, 880.209 kilojoules of heat are required to heat 2550 grams of water from 17.5°C to 100.0°C.

Learn more about how to calculate heat at: https://brainly.com/question/2530523

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