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i need help i dont get it

I Need Help I Dont Get It class=
I Need Help I Dont Get It class=

Sagot :

Answer:

2) x = [tex]\frac{5+\sqrt{57}}{8}[/tex], [tex]\frac{5-\sqrt{57}}{8}[/tex]

First, you need to begin by rearranging the equation into standard form. This would result to [tex]-4x^{2}[/tex]+5x+2. Because the first term cannot be a negative, you need to multiply the equation by -1, in order to eliminate the negative. This would result with [tex]4x^{2}[/tex]-5x-2.

There are many different methods when factoring a quadratic equation, including X-Method, Factoring by grouping, GCF, Quadratic Formula, etc. In this case, we will utilize quadratic formula. Quadratic formula is [tex]\frac{-b±\sqrt b^{2}-4ac}{2a}[/tex]

Quadratic equations always follow this variable format: [tex]ax^{2}[/tex]+bx+c. By using this format, we can use the corresponding numbers to solve the quadratic formula. This would result with [tex]\frac{5±\sqrt{-5^{2}-4(4)(-2)}}{2(-4)}[/tex]. Simplify the equation to get [tex]\frac{5±\sqrt{57}}{8}[/tex]. (Ignore the A)

10) C

When looking at [tex]4x^{2}[/tex]-5x-2, the leading coefficient would be 4 and the constant would be -2. The middle coefficient would be -5 and the highest degree would be 2. The answer isn't A, because it's true that the degree is less than the number of terms. (There are 3 terms and the degree is 2.) It isn't B, because it's true that -2 is less than 4. It isn't D, because it's true that -2 is less than -5. The answer is C, because the a-value, 4, is not less than the b-value, -5.

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