Answer:
2) x = [tex]\frac{5+\sqrt{57}}{8}[/tex], [tex]\frac{5-\sqrt{57}}{8}[/tex]
First, you need to begin by rearranging the equation into standard form. This would result to [tex]-4x^{2}[/tex]+5x+2. Because the first term cannot be a negative, you need to multiply the equation by -1, in order to eliminate the negative. This would result with [tex]4x^{2}[/tex]-5x-2.
There are many different methods when factoring a quadratic equation, including X-Method, Factoring by grouping, GCF, Quadratic Formula, etc. In this case, we will utilize quadratic formula. Quadratic formula is [tex]\frac{-b±\sqrt b^{2}-4ac}{2a}[/tex]
Quadratic equations always follow this variable format: [tex]ax^{2}[/tex]+bx+c. By using this format, we can use the corresponding numbers to solve the quadratic formula. This would result with [tex]\frac{5±\sqrt{-5^{2}-4(4)(-2)}}{2(-4)}[/tex]. Simplify the equation to get [tex]\frac{5±\sqrt{57}}{8}[/tex]. (Ignore the A)
10) C
When looking at [tex]4x^{2}[/tex]-5x-2, the leading coefficient would be 4 and the constant would be -2. The middle coefficient would be -5 and the highest degree would be 2. The answer isn't A, because it's true that the degree is less than the number of terms. (There are 3 terms and the degree is 2.) It isn't B, because it's true that -2 is less than 4. It isn't D, because it's true that -2 is less than -5. The answer is C, because the a-value, 4, is not less than the b-value, -5.
