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A rock is thrown from the top of a building . The height, h, of the rock t seconds after it thrown is given by h(t) = - 16t ^ 2 - 2t + 240 . How long will it take the rock to reach a height of 180 feet?

Sagot :

Answer:

1.875 sec

Step-by-step explanation:

Let h(t) = 180

180 = -16t^2 - 2t + 240

16t^2 + 2t - 60 = 0

2(8t^2 + t - 30) = 0

2(t + 2)(8t - 15) = 0

t = -2  or t = 15/8= 1.875 sec

Note:  time cannot be negative, so -2 is disregarded

shubhamchouhanvrVT

The time is taken by the rock to reach the height of 180 feet is 1.875 sec

What is an equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

The solution will be:-

Let h(t) = 180

180 = -16t²- 2t + 240

16t² + 2t - 60 = 0

2(8t² + t - 30) = 0

2(t + 2)(8t - 15) = 0

t = -2  or t = 15/8= 1.875 sec

Therefore the time is taken by the rock to reach the height of 180 feet is 1.875 sec

To know more about equations follow

https://brainly.com/question/2972832

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