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Researchers are attempting to create a new battery based on the following chemistry and would like the battery to produce 1.0-1.2 volts. Given the standard cell potential of the reaction, they propose to connect 3 identical cells inside the single new battery. Calculate the voltage of this (3-cell) battery at 25 C when 1.3 M Fe and 0.010 M Fe in pH 3.1 buffer react with O at 0.20 atm. (For full credit your answer must be correct to /-0.02.)

Sagot :

Answer:

Hello your question has some missing data attached below is the missing data ( Note: the PH in the attached question is 3.2 but the PH value I used in the solution = 3.1 as requested in the initial question )

answer : 0.41 volts

Explanation:

Given data :

[ Fe²⁺ ] = 1.3 M

[ Fe³⁺ ] = 0.010 M

[ H⁺ ] = 10^3.1

O2 = 0.20 atm

E⁰cell = 0.46 volts

temperature = 25°C ( room temperature )

Calculate the voltage of this ( 3 -cell battery )

we can apply the relation below

E = E⁰cell - ( 0.0591 / n )*Log Q

  = 0.46 - ( 0.0591 / 4 )*Log [ (0.01)^4 / (1.3)^4 * (10^3.1)^4 * 0.2 ]

  = 0.4120 Volts

Note : Q is determined from the equation attached to the question

View image batolisis