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Sagot :
Answer:
Test statistic = 3.21;
Pvalue = 0.0019;
Reject H0 and conclude that the mean conversion rate is greater than 30.
Step-by-step explanation:
Hypothesis :
NULL ; H0 : μ = 30
ALTERNATIVE ; H0 : μ > 30
Sample, x : 52.3 41.1 28.8 67.8 78.6 72.3 9 19.0 30.3 41.0 63.0 80.8 26.8 37.3 38.1 33.6 14.3 30.1 33.4 36.2 34.6 40.0 81.2 59.4
Sample Mean, xbar = 43.71 (using calculator)
Sample standard deviation, s = 20.95 ( calculator)
Sample size, n = 24
Take, α = 0.05
Test statistic :
(xbar - μ) ÷ (s/√n)
(43.71 - 30) ÷ (20.95/√24)
13.71 / 4.2764008
Test statistic = 3.21
Degree of freedom, df = n - 1 = 24 - 1 = 23
The Pvalue, using a Pvalue calculator : (3.21, 23)
Pvalue = 0.001942
Pvalue = 0.0019 ( 4 decimal places).
Decison :
Reject H0 ; if Pvalue ≤ α
Since Pvalue is very low and lesser than α ` We reject H0 and conclude that the mean conversion rate is greater than 30.
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