Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Answer: G
This problem requires you to utilize the equation for the volume of a sphere. The volume of a sphere is [tex]\frac{4}{3}\pi r^{2}[/tex]. Because we are given the radius, the equation should be [tex]\frac{4}{3}\pi 12^{2}[/tex]. Simplify the equation to get 7238.23 [tex]cm^{3}[/tex]. (The mass doesn't really matter in this scenario. It's just additional information.)
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.