Answered

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8. What is the kinetic energy of a 0.02 kg bullet that is traveling 300 m/s? Express your answer in joules.​

Sagot :

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900J

Explanation:
Well, kinetic energy is expressed through the equation:
KE
=
1
2
m
v
2

m
is the mass of the object in kilograms

v
is the velocity of the object in meters per second

So, we plug in the values, which are
m
=
0.02

kg

v
=
300

m/s

And we get,
KE
=
1
2
⋅
0.02

kg
⋅
(
300

m/s
)
2

=
1
2
⋅
0.02

kg
⋅
90000

m
2
/s
2

=
900

kg m
2
/s
2

=
900J

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