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Sagot :
Answer:
p-value = 0,000755
We reject H₀. We can support that Americans who are dissatisfied with education in kindergarten throug grade 12 differs significantly from 50%
Step-by-step explanation:
Sample proportion : p₁ = 0,55
Sample size n = 1000
q₁ = 1 - p₁ q₁ = 1 - 0,55 q₁ = 0,45
Hypothesis Test:
Null Hypothesis H₀ p₁ = 0,5 ( 50 % )
Alternative Hypothesis Hₐ p₁ ≠ 0,5
Alternative hypothesis indicates that we have to develop a two-tail test
as n = 1000
p₁*n = 0,55 * 1000 = 550 q₁*n = 0,45*1000 = 450
Both products are bigger than 5. We can use the approximation of binomial distribution to normal distribution.
Significance level α = 5% α = 0,05 and α/2 = 0,025
z(s) = ( p₁ - 0,5 ) / √p₁*q₁/1000
z(s) = 0,05 * 31,62 / 0,4974
z(s) = 3,1785
From z-table we find p-value = 0,000755
Therefore p-value < 0,025
We are in the rejection region, we reject H₀
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