Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
a) ω = 8.75 rad/s
b) I = 12.9 kgm^2
Explanation:
Given data:
Radius of the wheel r = 0.400 m
Speed of the suitcase v = 3.50 m/s
Height h = 4.00 m
Mass of the suitcase m = 15 kg
a) To determine angular velocity of the wheel when the suitcase reaches the ground is
we know that , ω = v / r
ω = (3.50 m/s) / (0.400 m )
ω = 8.75 rad/s
b) From the conservation of energy
we have KEi + Ui = KEf + Uf
where KEi , KEf are initial and final kinetic energies and Ui and Uf are initial and final potentail energies.
We know that KEi = 0 and Uf = 0
Ui = KEf
mgh = (1/2)mv^2 + (1/2) Iω^2
I = moment of inertia of wheel to determined
15×9.8×4 = (1/2) (15)(3.5)^2 + (1/2) I (8.75)^2
Calculating we get
I = 12.9 kgm^2
A force that acts on a body moving in a circular path and is directed toward the center around which the body is moving.
According to the question, The formula is used to find the omega is:-
[tex]w =\frac{v}{r}[/tex]
[tex]w= \frac{3.50}{0.400}[/tex]
Hence, the omega is ω = 8.75 rad/s
From the conservation of energy we have KEi + Ui = KEf + Uf
where Kei, KEf are initial and final kinetic energies and Ui and Uf are initial and final potential energies.
We know that KEi = 0 and Uf = 0
So, therefore the Ui = KEf
Hence [tex]mgh = \frac{1}{2}mv^{2} + \frac{1}{2} Iw^{2}[/tex]
After putting the value:-
[tex]15*9.8*4 = \frac{1}{2}*15*3.5^{2} + \frac{1}{2}*I*8.75^{2}[/tex]
Hence the value of I is[tex]12.9 kgm^2[/tex]
For more information, refer to the link:-
https://brainly.com/question/21338592
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
