Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Ray had a block of wood in the shape of a rectangular prism. The block and it's dimensions are shown below:

Sagot :

MrRoyal

Answer:

[tex](a)\ Area = 24in^2[/tex]

[tex](b)\ Area = 60in^2[/tex]

Step-by-step explanation:

Given

See attachment for the dimension of the block

Solving (a): Area of the front face

From the attachment, the front face has the following dimension.

[tex]Length = 4in[/tex]

[tex]Width = 6in[/tex]

The area is calculated as:

[tex]Area = Length *Width[/tex]

[tex]Area = 4in * 6in[/tex]

[tex]Area = 24in^2[/tex]

Solving (b): Area of the top and bottom faces

The top and bottom faces have the same dimension

From the attachment, the top face has the following dimension.

[tex]Length = 5in[/tex]

[tex]Width = 6in[/tex]

The area of the top is calculated as:

[tex]Area = Length *Width[/tex]

[tex]A_1 = 5in * 6in[/tex]

[tex]A_1 = 30in^2[/tex]

The area of the top and the bottom faces is:

[tex]Area = 2 *A_1[/tex] ---- because the top and bottom faces have the same dimension

[tex]Area = 2 *30in^2[/tex]

[tex]Area = 60in^2[/tex]

View image MrRoyal
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.