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Ray had a block of wood in the shape of a rectangular prism. The block and it's dimensions are shown below:

Sagot :

Answer:

[tex](a)\ Area = 24in^2[/tex]

[tex](b)\ Area = 60in^2[/tex]

Step-by-step explanation:

Given

See attachment for the dimension of the block

Solving (a): Area of the front face

From the attachment, the front face has the following dimension.

[tex]Length = 4in[/tex]

[tex]Width = 6in[/tex]

The area is calculated as:

[tex]Area = Length *Width[/tex]

[tex]Area = 4in * 6in[/tex]

[tex]Area = 24in^2[/tex]

Solving (b): Area of the top and bottom faces

The top and bottom faces have the same dimension

From the attachment, the top face has the following dimension.

[tex]Length = 5in[/tex]

[tex]Width = 6in[/tex]

The area of the top is calculated as:

[tex]Area = Length *Width[/tex]

[tex]A_1 = 5in * 6in[/tex]

[tex]A_1 = 30in^2[/tex]

The area of the top and the bottom faces is:

[tex]Area = 2 *A_1[/tex] ---- because the top and bottom faces have the same dimension

[tex]Area = 2 *30in^2[/tex]

[tex]Area = 60in^2[/tex]

View image MrRoyal
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