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Sagot :
Answer:
The molar mass of the gas is 99.4 g/mol
Explanation:
Ideal gas law PV=nRT. P=155.3 T=127+273= 400K V=25.0 Gas constant=8.314 Now substiture the values into the equation n=PV/RT
n= (155.5kPa x 25.0mL x 1l/1000mL)/ 8.312l*KPa/mol*K x 400K
n= 0.001167 mol
Molar mass= Mass/ Number of moles
= 0.116g /0.001167 mol
= 99.4 g/mol
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