Answer: The correct answer is 28.8.(deltamath)
Step-by-step explanation:
The perimeter of the considered isosceles triangle is 28.8 in. approx.
If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:
[tex]|AC|^2 = |AB|^2 + |BC|^2[/tex]
where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).
Considering the attached image below, which has same isosceles triangle with same measurements, we see that:
|AC| = |AB| (because perpendicular dropped leaves two congruent triangles in ABC, as ADC and ADB)
similarly, we have:
|BD| = |DC|
But |BC| = 6 = |BD| + |DC|,
Thus, 6 = |BD| + |DC| = |BD| + |BD| =2|BD|
|BD| = 6/2 = 3 inches = |DC|
From Pythagoras theorem for triangle ADB, we get:
[tex]|AB|^2 = |AD|^2 + |BD|^2\\|AB|^2 = 11^2 + 3^2 = 121 + 9 = 130\\|AB| = \sqrt{130} \approx 11.4 \: \rm in. = |AC|[/tex]
(positive square root since |AB| is length, which is a non-negative measure).
Thus, we get:
Perimeter of the rectangle = |AB| + |BC| + |AC| ≈ 11.4 + 6 + 11.4 = 28.8 in.
Learn more about Pythagoras theorem here:
https://brainly.com/question/12105522
