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Sagot :
The image is either virtual or real and the height of the image is 10cm.
To find the image type and its height, we need to know about the magnification of convex lens.
What is magnification of an image formed by lens?
- magnification of an image is the comparison of the image size with respect to that of object.
- It's the ratio of image height to that of object height.
What is the mathematical formula of magnification of image?
- Mathematically, the magnification of an image is
Height of image/height of object or image distance(V) / object distance(U)
- If the magnification is positive, image is virtual and if it's negative, the image is real.
What is the magnification, if image distance is 48cm and object distance is 24 cm?
- Object is placed on the left of the lens and the object distance is taken as negative using sign convention.
- If the image is also formed on the left, the image distance is taken as negative. Corresponding magnification is -48cm/-24cm = 2. Since, the magnification is positive, so, image is virtual.
- But, if the image is formed on the right of the lens at 48cm, the image distance is taken as positive. So the magnification is 48cm/(-24)cm = -2. Since, the magnification is negative, so image is real.
What is the image height, absolute value of magnification is 2 and object height is 5cm?
- Magnification = image height / object height
So, image height = magnification × object height
= 2×5 = 10 cm
Thus, we can conclude that the image is virtual if it's formed on the left of the lens and is real if it's formed on the right of the lens. The height of the image is 10 cm.
Learn more about magnification of image here:
https://brainly.com/question/3480304
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