Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

How many moles of a gas sample are in a 5.0 L container at 373 K and 203 kPa?

0.33 mole

0.66 mole

1.11 moles

3.05 moles

Sagot :

maacastrobr

Answer:

0.33 moles.

Explanation:

Assuming the gas is ideal, we can solve this problem by using the following formula:

  • PV = nRT

Where:

  • P = 203 kPa
  • V = 5.0 L
  • n = ?
  • R = 8.314 kPa·L·mol⁻¹·K⁻¹
  • T = 373 K

We input the data:

  • 203 kPa * 5.0 L = n * 8.314 kPa·L·mol⁻¹·K⁻¹ * 373 K
  • n = 0.327 mol

The answer is thus the first option, 0.33 moles.

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.