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Find the missing side lengths. Leave your answers as radicals in simplest form.
Please help!!!! Due today please help!!!!!!

Find The Missing Side Lengths Leave Your Answers As Radicals In Simplest Form Please Help Due Today Please Help class=

Sagot :

MrRoyal

Answer:

[tex]m = 10\sqrt 3[/tex]

[tex]n = 10[/tex]

Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

[tex]\sin(60) = \frac{Opposite}{Hypotenuse}[/tex]

This gives:

[tex]\sin(60) = \frac{m}{20}[/tex]

Make m ths subject

[tex]m = 20 * \sin(60)[/tex]

[tex]\sin(60) =\frac{\sqrt 3}{2}[/tex]

So, we have:

[tex]m = 20 *\frac{\sqrt 3}{2}[/tex]

[tex]m = 10\sqrt 3[/tex]

Considering the given angle again, we have:

[tex]\cos(60) = \frac{Adjacent}{Hypotenuse}[/tex]

This gives:

[tex]\cos(60) = \frac{n}{20}[/tex]

Make n the subject

[tex]n = 20 * \cos(60)[/tex]

[tex]\sin(60) =\frac{1}{2}[/tex]

So, we have:

[tex]n = 20 *\frac{1}{2}[/tex]

[tex]n = 10[/tex]

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