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what is an equation of the line that passes through point (-6,-5) and is parallel to the line x + 5y=25

Sagot :

hbj

Answer:

y = -1/5x - 31/5

Step-by-step explanation:

If two lines are parallel to each other, they have the same slope.

The first line is x + 5y = 25.

First, let's put this in standard form of y = mx + b.

x + 5y = 25

Subtract x from both sides.

5y = -x + 25

Divide each term by 5.

y = -1/5x + 5

This line's slope is -1/5. A line parallel to this one will also have a slope of -1/5.

Plug this value (-1/5) into your standard point-slope equation of y = mx + b.

y = -1/5x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (-6, -5). Plug in the x and y values into the x and y of the standard equation.

-5 = -1/5(-6) + b

To find b, multiply the slope and the input of x (-6)

-5 = 6/5 + b

Now, subtract 6/5 from both sides to isolate b.

-5 - 6/5 = b

-25/5 - 6/5 = b

-31/5 = b

Plug this into your standard equation.

y = -1/5x - 31/5

This equation is parallel to your given equation (y = -1/5x + 5) and contains point (-6, -5)

Hope this helps!

View image hbj
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