Given:
[tex]m\angle B=90^\circ, m\angle D=90^\circ, AB=6, BD=4, BC=2, DE=x[/tex].
To find:
The value of x.
Solution:
In triangles ABC and ADE,
[tex]\angle B\cong \angle D[/tex] (Right angles)
[tex]\angle A\cong \angle A[/tex] (Common angles)
[tex]\Delta ABC\sim \Delta ADE[/tex] (AA property of similarity)
We know that the corresponding sides of similar triangles are proportional. So,
[tex]\dfrac{AB}{AD}=\dfrac{BC}{DE}[/tex]
[tex]\dfrac{6}{(6+4)}=\dfrac{2}{x}[/tex]
[tex]\dfrac{6}{10}=\dfrac{2}{x}[/tex]
[tex]\dfrac{3}{5}=\dfrac{2}{x}[/tex]
On cross multiplication, we get
[tex]3\times x=5\times 2[/tex]
[tex]3x=10[/tex]
[tex]x=\dfrac{10}{3}[/tex]
Therefore, the value of x is [tex]\dfrac{10}{3}[/tex] units.
