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A 752g sample of an unknown substance has its temperature increase by 8°C after being exposed to 1287.424 j,calculate the specific heat of
the substance. _____J/g*C (3 sig figs)

Sagot :

dsdrajlin

Answer:

0.214 J/g.°C

Explanation:

Step 1: Given data

  • Mass of the sample (m): 752 g
  • Temperature increase (ΔT): 8 °C
  • Provided heat (Q): 1287.424 J

Step 2: Calculate the specific heat of the substance (c)

The specific heat of the substance is an intrinsic property of a substance. We can calculate it using the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1287.424 J / 752 g × 8 °C = 0.214 J/g.°C

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