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Steve ran a 26-mile race at an average speed of 4 miles per hour. If Adam ran the same race at an average speed of 3 miles per hour, how many minutes longer did Adam take to complete the race than did Steve?

Sagot :

whitneytr12

Answer:

Adam took 132 minutes longer than Steve.

Step-by-step explanation:

Let's find the time that takes Steve and Adam to complete the race. We will use the equation:

[tex] V = \frac{d}{t} [/tex]              

Where:

d: is the distance = 26 miles

t: is the time =?

V: is the speed

For Steve we have the following time:

[tex] t_{s} = \frac{d}{V_{s}} = \frac{26 mi}{4 mi/h} = 6.5 h*\frac{60 min}{1 h} = 390 min [/tex]

And the time of Adam is:

[tex] t_{a} = \frac{d}{V_{a}} = \frac{26 mi}{3 mi/h} = 8.7 h*\frac{60 min}{1 h} = 522 min [/tex]

So, the difference between the time of Adam and Steve is:

[tex] \Delta t = t_{a} - t_{s} = 522 min - 390 min = 132 min [/tex]

Hence, Adam took 132 minutes longer than Steve.

I hope it helps you!

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