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Find the final velocity of a 40 kg skateboarder traveling at an initial velocity of 10 m/s that moves up a hill from a height of 0 m to a height of 5 m. Assume gravity is 10 m/s2.
½ m vi2 + m g hi = ½ m vf2 + m g hf

Group of answer choices:
14 m/s

20 m/s

10 m/s

0 m/s

Sagot :

Trancescient

Answer:

vf = 0

Explanation:

Since the initial height hi = 0, we can rewrite the energy equation as

vf^2 = vi^2 - 2ghf = (10 m/s)^2 - 2(10 m/s^2)(5 m) = 0

Therefore, his final velocity vf is

vf = 0

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