Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

The circle below is centered at the point (4,-3) and has a radius of length 3. What is its equation? 6 O A. (x - 4)2 + (y + 3)2 - 32 W O B. (x-3)2 + (y + 4)2 = 9 ОООО C. (X- 3)2 + (y - 4)2 = 9 D. (x + 4)2 + (y - 3)2 = 32. ​

The Circle Below Is Centered At The Point 43 And Has A Radius Of Length 3 What Is Its Equation 6 O A X 42 Y 32 32 W O B X32 Y 42 9 ОООО C X 32 Y 42 9 D X 42 Y 3 class=

Sagot :

ivycoveredwalls

Answer:

[tex](x-4)^2+(y+3)^2=9[/tex]

Step-by-step explanation:

Standard Form equation of a circle with center (h, k) and radius r:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Plug in given values: h = 4, k = -3, r = 3.

[tex](x-4)^2+[y-(-3)]^2=3^2\\\\(x-4)^2+(y+3)^2=9[/tex]

The tricky part can be the sign in the y squard term:  y - (-3) = y + 3.

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.