Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Assume there exists some hypothetical metal that exhibits ferromagnetic behavior and that has (1) a simple cubic crystal structure, (2) an atomic radius of 0.126 nm, and (3) a saturation flux density of 0.69 tesla. Determine the number of Bohr magnetons per atom for this material. Part 1 Correct answer icon Excellent! What is the volume, in m3, for this unit cell

Sagot :

okpalawalter8

Answer:

[tex]n_b=0.947 Bohr\ magnetons/atom[/tex]

Explanation:

From the question we are told that:

Atomic radius [tex]r=0.126 nm[/tex]

Saturation flux density [tex]B= 0.69 T[/tex]

Generally the equation for number of Bohr magnetons per atom is mathematically given by

 [tex]n_b=\frac{B_s*Vc}{\mu_0*\mu_b}[/tex]

Where

 [tex]\mu_0=Magnetic\ permeability[/tex]

 [tex]\mu_0=1.257 * 10^{-6}[/tex]

 [tex]\mu_b=Magnetic\ Moment\ of\ an\ Atom[/tex]

 [tex]\mu_b=9.27* 10^{-24}[/tex]

 [tex]Vc=d^3[/tex]

 [tex]Vc=(2(0.126*10^-9))^3[/tex]

 [tex]Vc=1.6*10^{-29}[/tex]

Therefore the number of Bohr magnetons per atom for this material

 [tex]n_b=\frac{0.69*1.6*10^{-29}}{1.257 * 10^{-6}*9.27* 10^{-24}}[/tex]

 [tex]n_b=0.947 Bohr\ magnetons/atom[/tex]

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.