Answer:
55 feet
Step-by-step explanation:
If you draw it out, the diagnonal along wiht 2 sides of the rectangle make a rigth angles traingle.
Using pythagoras theoreom, [tex]c^{2} =a^{2} +b^{2}[/tex], c is the length of the diagonal and a and b are 2 sides of rectangle.
So c=[tex]\sqrt{a^{2} +b^{2} }[/tex]
=[tex]\sqrt{33^{2} +44^{2} }[/tex]
put in alculator and get:
55
=55 feet
The measure of the diagonal of the rectangle plot which has the measure of 33 feet by 44 feet is 55 feet.
The diagonal of the rectangle is the distance from opposite vertices of it. There are two diagonals in a rectangle which are equal in measure.
To find the diagonal of the rectangle, the following formula is used.
[tex]d=\sqrt{l^2+w^2}[/tex]
Here, (l) is the length of the rectangle and (w) is the width of it.
The width of the rectangular plot measures 33 feet and length measure 44 feet. Plug in these values in the above formula to find the diagonal of the plot.
[tex]d=\sqrt{(44)^2+(33)^2}\\d=\sqrt{1936+1089}\\d=\sqrt{325}\\d=55\rm\; ft[/tex]
Hence, the measure of the diagonal of the rectangle plot which has measure of 33 feet by 44 feet is 55 ft.
Learn more about the diagonal of the rectangle here;
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