Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
Option E
Explanation:
As we know
[tex]m = \frac{-2RU}{GM} \\[/tex]
Where R is the radius of the orbit
G is the gravitational Constant =[tex]6.67*10^{-11}[/tex]
U is the total energy and
M is the mass of Earth [tex]= 5.98*10^{24}[/tex]
radius of earth [tex]= 6.378*10^6[/tex]
Radius of the orbit = radius of the earth [tex]+ 650[/tex] km
Radius of the orbit (R) = [tex](6.378*10^6)+(6.5*10^5)[/tex]
Substituting the given values, we get -
[tex]m = \frac{ (2((6.378*10^6)+(6.5*10^5))(-4.4*10^{11}))}{((6.67*10^{-11})(5.98*10^{24}))}\\ = 15505.6[/tex]
Option E is the nearest answer
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.